树与图的深度优先遍历

知识点
- dfs
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 100;
int h[N], e[N], ne[N], idx;
int n, m;
bool st[N];
void add(int a, int b){
e[idx] = b, ne[idx] = h[a], h[a] = idx ++;
}
void dfs(int u){
st[u] = true;
for(int i = h[u]; i != -1; i = ne[i]){
int j = e[i];
if(!st[j])
dfs(j);
}
}
int main(){
memset(h, -1, sizeof h);
dfs(1);
}
解题思路
实现代码
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